Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
The carbonate ion, , has three canonical forms. Each has one C=O and two C-O bonds. Find the bond order of each carbon to oxygen bond in the hybrid, and the average formal charge on each oxygen. Give answers to two decimal places.
A higher bond order gives a shorter, stronger bond. The bond order in a resonance hybrid is the average over its canonical forms. Dipole moment: , with C m. Percent ionic character measured dipole dipole if fully ionic .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Bond order. Each form has bonds over three positions: .
Step 2. Formal charge. Each form has a total of on the oxygens: on each.
Step 3. Meaning. All three bonds are the same length, between a single and a double bond.
Answer: bond order ; average formal charge .
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