A brief note on Potential Energy and Conservation of Energy . Read it before a test. Try each question at the end before you open its answer.
The big ideas A conservative force (gravity, a spring) does work that depends only on the start and the end. Friction and drag are not conservative. Potential energy : W = − Δ U W = -\Delta U W = − Δ U . Gravity near the Earth: U = m g h U = mgh U = m g h . A spring: U = 1 2 k x 2 U = \tfrac12 kx^2 U = 2 1 k x 2 . Force from U U U : F = − d U d x F = -\dfrac{dU}{dx} F = − d x d U . A minimum of U U U is a stable equilibrium. Conservation : with only conservative forces working, K + U K + U K + U stays the same. With friction : K 1 + U 1 = K 2 + U 2 + E heat K_1 + U_1 = K_2 + U_2 + E_{\text{heat}} K 1 + U 1 = K 2 + U 2 + E heat . The facts at a glance Fall from rest through h h h : v = 2 g h v = \sqrt{2gh} v = 2 g h , whatever the path Spring launcher: v = x k m v = x\sqrt{\dfrac{k}{m}} v = x m k Pendulum from θ 0 \theta_0 θ 0 : v = 2 g L ( 1 − cos θ 0 ) v = \sqrt{2gL(1 - \cos\theta_0)} v = 2 g L ( 1 − cos θ 0 ) at the bottom Loop of radius R R R : start at least 2.5 R 2.5R 2.5 R high String in a vertical circle: at least 5 g L \sqrt{5gL} 5 g L at the bottom, g L \sqrt{gL} g L at the top A worked example A 1.2 kg 1.2\ \text{kg} 1.2 kg ball is thrown straight down at 3.0 m/s 3.0\ \text{m/s} 3.0 m/s from a window 2.2 m 2.2\ \text{m} 2.2 m above the ground. How fast does it land?
Energy at the window. 1 2 m u 2 + m g h \tfrac12 mu^2 + mgh 2 1 m u 2 + m g h . Energy at the ground. 1 2 m v 2 \tfrac12 mv^2 2 1 m v 2 . Set them equal. v = u 2 + 2 g h = 9.0 m 2 / s 2 + 43.1 m 2 / s 2 = 7.22 m/s v = \sqrt{u^2 + 2gh} = \sqrt{9.0\ \text{m}^2/\text{s}^2 + 43.1\ \text{m}^2/\text{s}^2} = 7.22\ \text{m/s} v = u 2 + 2 g h = 9.0 m 2 / s 2 + 43.1 m 2 / s 2 = 7.22 m/s . The mass cancels, and the answer is the same if the ball is thrown up or sideways at 3.0 m/s 3.0\ \text{m/s} 3.0 m/s . Practice with new numbers
A program to try The program follows a skateboarder down a ramp, with no losses and with 15 % 15\% 15% lost to friction.
Read it, then run it.
What fraction of the ideal speed is the real speed at every height? Why is it the same at every height?
Mistakes to avoid Height above the ground instead of distance fallen. Use the drop between the two points. The value of U U U as if it were absolute. Only changes in U U U matter; zero can be anywhere. Forgetting the minus in F = − d U d x F = -\dfrac{dU}{dx} F = − d x d U . Energy conserved with friction. Mechanical energy is not; the heat must be counted. 2 R 2R 2 R as the least height for a loop. It is 2.5 R 2.5R 2.5 R . Check yourself A 2.0 kg 2.0\ \text{kg} 2.0 kg stone falls from 15 m 15\ \text{m} 15 m . What is its kinetic energy 5.0 m 5.0\ \text{m} 5.0 m above the ground? ( g = 9.8 m/s 2 g = 9.8\ \text{m/s}^2 g = 9.8 m/s 2 .) Stuck? Show a hint Show the answerU ( x ) = 4 x 2 U(x) = 4x^2 U ( x ) = 4 x 2 joules. What is the force at x = − 0.5 m x = -0.5\ \text{m} x = − 0.5 m ? Stuck? Show a hint Show the answerA spring with k = 900 N/m k = 900\ \text{N/m} k = 900 N/m is squeezed 4.0 cm 4.0\ \text{cm} 4.0 cm and launches a 0.10 kg 0.10\ \text{kg} 0.10 kg ball along a smooth table. How fast does it go? Stuck? Show a hint Show the answerA 50 kg 50\ \text{kg} 50 kg child slides down a 3.0 m 3.0\ \text{m} 3.0 m high slide and lands at 5.0 m/s 5.0\ \text{m/s} 5.0 m/s . How much energy became heat? ( g = 9.8 m/s 2 g = 9.8\ \text{m/s}^2 g = 9.8 m/s 2 .) Stuck? Show a hint Show the answerWhat least speed at the top keeps a stone on a 0.60 m 0.60\ \text{m} 0.60 m string moving in a vertical circle? ( g = 9.8 m/s 2 g = 9.8\ \text{m/s}^2 g = 9.8 m/s 2 .) Stuck? Show a hint Show the answer