A brief note on Current, Drift Velocity and Resistivity . Read it before a test. Try each question at the end before you open its answer.
Current and the drift Current: I = Q / t I = Q/t I = Q / t , in A. The number of electrons is N = Q / e N = Q/e N = Q / e , with e = 1.6 × 10 − 19 e = 1.6 \times 10^{-19} e = 1.6 × 1 0 − 19 C. Without a field: the free electrons move at random and the motions cancel. With a field: a slow drift, v d = e E m τ v_d = \dfrac{eE}{m}\tau v d = m e E τ , against the field. Mobility: μ = v d E = e τ m \mu = \dfrac{v_d}{E} = \dfrac{e\tau}{m} μ = E v d = m e τ , in m 2 / ( V s ) \text{m}^2/(\text{V s}) m 2 / ( V s ) . Current: I = n A e v d I = nAev_d I = n A e v d . Current density: J = I A = n e v d J = \dfrac{I}{A} = nev_d J = A I = n e v d . Drift speeds are fractions of a millimetre each second. The field spreads at nearly the speed of light. Resistivity and conductivity Ohm's law at the level of the material: J = σ E J = \sigma E J = σ E , with σ = n e 2 τ m = n e μ \sigma = \dfrac{ne^2\tau}{m} = ne\mu σ = m n e 2 τ = n e μ . Resistivity: ρ = 1 σ = m n e 2 τ \rho = \dfrac{1}{\sigma} = \dfrac{m}{ne^2\tau} ρ = σ 1 = n e 2 τ m , in Ω \Omega Ω m. A wire: R = ρ L A R = \rho\dfrac{L}{A} R = ρ A L , with A = π d 2 4 A = \dfrac{\pi d^2}{4} A = 4 π d 2 for a round wire. Materials: metals about 10 − 8 Ω 10^{-8}\ \Omega 1 0 − 8 Ω m, semiconductors in between, insulators 10 10 Ω 10^{10}\ \Omega 1 0 10 Ω m and more. A wire cut into n n n pieces joined side by side has R / n 2 R/n^2 R / n 2 . Temperature and the colour code Metals: R T = R 0 [ 1 + α ( T − T 0 ) ] R_T = R_0[1 + \alpha(T - T_0)] R T = R 0 [ 1 + α ( T − T 0 )] , with α \alpha α positive. Resistance rises with temperature. Semiconductors: α \alpha α is negative. Alloys such as manganin: α \alpha α is almost zero. Superconductors: zero resistance below a critical temperature. Not ohmic: a filament lamp and a diode do not give a straight line of I I I against V V V . Colour code: digit, digit, power of ten, tolerance. Gold ± 5 % \pm 5\ \% ± 5 % , silver ± 10 % \pm 10\ \% ± 10 % , none ± 20 % \pm 20\ \% ± 20 % . A worked example A wire of cross section 4.0 mm 2 4.0\ \text{mm}^2 4.0 mm 2 carries 12 12 12 A. Find the current density, and the drift speed if n = 8.5 × 10 28 m − 3 n = 8.5 \times 10^{28}\ \text{m}^{-3} n = 8.5 × 1 0 28 m − 3 .
Current density. J = 12 A 4.0 × 10 − 6 m 2 = 3.0 × 10 6 A/m 2 J = \dfrac{12\ \text{A}}{4.0 \times 10^{-6}\ \text{m}^2} = 3.0 \times 10^6\ \text{A/m}^2 J = 4.0 × 1 0 − 6 m 2 12 A = 3.0 × 1 0 6 A/m 2 . Drift speed. v d = J n e = 3.0 × 10 6 8.5 × 10 28 × 1.6 × 10 − 19 = 2.2 × 10 − 4 m/s v_d = \dfrac{J}{ne} = \dfrac{3.0 \times 10^6}{8.5 \times 10^{28} \times 1.6 \times 10^{-19}} = 2.2 \times 10^{-4}\ \text{m/s} v d = n e J = 8.5 × 1 0 28 × 1.6 × 1 0 − 19 3.0 × 1 0 6 = 2.2 × 1 0 − 4 m/s . Practise with new numbers
Check yourself A wire is made twice as long and its diameter is made half, with the same metal. By what factor does its resistance change? Stuck? Show a hint Show the answerA coil of copper has 50 Ω 50\ \Omega 50 Ω at 20 ∘ 20\ ^\circ 20 ∘ C. Estimate its resistance at 120 ∘ 120\ ^\circ 120 ∘ C, with α = 3.9 × 10 − 3 \alpha = 3.9 \times 10^{-3} α = 3.9 × 1 0 − 3 per ∘ ^\circ ∘ C. Stuck? Show a hint Show the answerWhy does the resistance of a thermistor fall when it warms? Stuck? Show a hint Show the answer