A brief note on Current, Potential Difference and Ohm's Law . Read it before a test. Try each question at the end before you open its answer.
The big ideas Current is the charge passing each second: I = Q t I = \dfrac{Q}{t} I = t Q , in amperes. An electron carries 1.6 × 10 − 19 C 1.6 \times 10^{-19}\ \text{C} 1.6 × 1 0 − 19 C . The conventional current goes from + + + to − - − outside the cell; the electrons drift the other way. Potential difference is the work per coulomb: V = W Q V = \dfrac{W}{Q} V = Q W , in volts. Ohm's law : at a steady temperature, V = I R V = IR V = I R . The V-I graph is a straight line through the origin, with slope R R R . An ammeter goes in series (tiny resistance); a voltmeter goes in parallel (huge resistance). The facts at a glance Quantity Symbol Rule Unit Charge Q Q Q Q = I t Q = It Q = I t coulomb (C) Current I I I I = Q t I = \dfrac{Q}{t} I = t Q ampere (A) Potential difference V V V V = W Q V = \dfrac{W}{Q} V = Q W volt (V) Resistance R R R R = V I R = \dfrac{V}{I} R = I V ohm ( Ω \Omega Ω )
A worked example A current of 0.45 A 0.45\ \text{A} 0.45 A flows for 3 3 3 minutes through a 12 Ω 12\ \Omega 12 Ω resistor. Find the charge that passes and the potential difference across the resistor.
The time. 3 min = 180 s 3\ \text{min} = 180\ \text{s} 3 min = 180 s . The charge. Q = 0.45 A × 180 s = 81 C Q = 0.45\ \text{A} \times 180\ \text{s} = 81\ \text{C} Q = 0.45 A × 180 s = 81 C . The potential difference. V = I R = 0.45 A × 12 Ω = 5.4 V V = IR = 0.45\ \text{A} \times 12\ \Omega = 5.4\ \text{V} V = I R = 0.45 A × 12 Ω = 5.4 V . Practice with new numbers
A program to try The program works out the charge, the potential difference and the energy for one resistor.
Read it, then run it. It repeats the worked example.
1. Double the current. What happens to the charge, the voltage and the energy?
Mistakes to avoid Leaving the time in minutes in Q = I t Q = It Q = I t . Use seconds. Joining an ammeter in parallel. It would short the circuit. Thinking current is used up in a bulb. The same current flows in and out; energy is what is used. Applying Ohm's law to a hot filament. Its resistance changes as it heats. Check yourself A charge of 54 C 54\ \text{C} 54 C passes in 15 s 15\ \text{s} 15 s . What is the current? Stuck? Show a hint Show the answerA voltmeter reads 2.2 V 2.2\ \text{V} 2.2 V across a wire, and an ammeter 0.08 A 0.08\ \text{A} 0.08 A through it. Find its resistance. Stuck? Show a hint Show the answerA 6 V 6\ \text{V} 6 V battery moves 3.5 C 3.5\ \text{C} 3.5 C . How much energy does it give? Stuck? Show a hint Show the answerTwo conductors have straight V-I lines. Which one has the larger resistance? Stuck? Show a hint Show the answer