Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Write the name of each compound.
Names are built in this order: cation, then anion. Inside the complex: ligands in alphabetical order (prefixes ignored), then the metal, then the oxidation state in Roman numerals. An anionic complex ends in -ate (ferrate, cuprate, argentate, aurate). Anionic ligands end in -o. is ammine and is aqua.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. . The complex is the cation. Two ammine ligands, and silver is : diamminesilver(I) chloride.
Step 2. . The complex is the anion. Four chlorido ligands give , and the complex is , so platinum is : potassium tetrachloridoplatinate(II).
Step 3. . The complex is the anion with a charge of . Gold is and takes its Latin name: sodium dicyanidoaurate(I).
Step 4. . The complex is because sulphate is : tetraamminecopper(II) sulphate.
Check. Each name has the cation first, then the ligands in alphabetical order, then the metal, then the Roman numeral.
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