A fair die is rolled twice. Let X be the number of sixes in the two rolls…

Step 1. No six. $5 \times 5 = 25$ pairs, so $P(X = 0) = \dfrac{25}{36} \approx 0.6944$.

Step 2. Two sixes. Only $(6, 6)$, so $P(X = 2) = \dfrac{1}{36} \approx 0.0278$.

Step 3. One six. The rest: $36 - 25 - 1 = 10$ pairs, so $P(X = 1) = \dfrac{10}{36} \approx 0.2778$.