Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A sample of bleach solution is added to excess potassium iodide in acid. Each hypochlorite ion frees one molecule of iodine: . The iodine needs of sodium thiosulfate, by . Find the moles of thiosulfate, the moles of iodine and the concentration of hypochlorite in the bleach.
At the end point, the moles of the two reagents are in the ratio of the balanced equation. Moles = concentration in mol/L times volume in litres. With n-factors, .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Thiosulfate. .
Step 2. Iodine. The ratio is , so .
Step 3. Hypochlorite. One iodine molecule comes from one hypochlorite ion, so there is of .
Step 4. Concentration. .
Answer: , and .
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