A 20.0 mL sample of iron(II) sulfate solution needs 16.0 mL of 0.0150 mol/L acidified potassium…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
A sample of iron(II) sulfate solution needs of acidified potassium permanganate to reach the end point. Find the moles of permanganate used, the moles of iron(II) in the sample and the concentration of iron(II).
Need a reminder? The key ideaShow
At the end point, the moles of the two reagents are in the ratio of the balanced equation. Moles = concentration in mol/L times volume in litres. With n-factors, .
The worked solution
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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. The sample is . The titre is of permanganate.
Step 1. Permanganate. .
Step 2. Iron(II). The ratio is , so .
Step 3. Concentration. .
Answer: of permanganate, of iron(II), and . Check. Equivalents: and .
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