A brief note on The Quantum Model and Electron Configurations . Read it before a test. Try each question at the end before you open its answer.
Waves and uncertainty De Broglie: λ = h m v \lambda = \dfrac{h}{mv} λ = m v h . Heisenberg: Δ x ⋅ m Δ v ≥ h 4 π \Delta x \cdot m\Delta v \geq \dfrac{h}{4\pi} Δ x ⋅ m Δ v ≥ 4 π h . No fixed orbit can be known. Quantum numbers Number Values Tells n n n 1 , 2 , 3 , … 1, 2, 3, \ldots 1 , 2 , 3 , … shell and size l l l 0 0 0 to n − 1 n - 1 n − 1 shape: s , p , d , f s, p, d, f s , p , d , f m l m_l m l − l -l − l to + l +l + l orientation m s m_s m s ± 1 2 \pm\tfrac{1}{2} ± 2 1 spin
A subshell has 2 l + 1 2l + 1 2 l + 1 orbitals; a shell has n 2 n^2 n 2 . Nodes: radial n − l − 1 n - l - 1 n − l − 1 , angular l l l .
Filling Aufbau: by ( n + l ) (n + l) ( n + l ) , the smaller n n n first for a tie. Pauli: at most two electrons in an orbital, with opposite spins. Hund: one electron in each orbital of a subshell before pairing. Chromium and copper move one 4 s 4s 4 s electron into 3 d 3d 3 d . Ions lose 4 s 4s 4 s first. Spin-only moment: μ = n ( n + 2 ) BM \mu = \sqrt{n(n + 2)}\ \text{BM} μ = n ( n + 2 ) BM . A worked example Manganese is [ Ar ] 3 d 5 4 s 2 [\text{Ar}]\,3d^5 4s^2 [ Ar ] 3 d 5 4 s 2 . Find the configuration and the magnetic moment of Mn 3 + \text{Mn}^{3+} Mn 3 + .
Remove three electrons. Two from 4 s 4s 4 s , then one from 3 d 3d 3 d : [ Ar ] 3 d 4 [\text{Ar}]\,3d^4 [ Ar ] 3 d 4 . Unpaired. Four electrons in five d d d orbitals, one each: 4 4 4 unpaired. Moment. μ = 4 × 6 = 4.90 BM \mu = \sqrt{4 \times 6} = 4.90\ \text{BM} μ = 4 × 6 = 4.90 BM . Practice with new numbers
A program to try The program works out the worked example.
Read it, then run it. Does it agree with the worked example?
1. Change d to 8, as in Ni 2 + \text{Ni}^{2+} Ni 2 + . How many electrons are unpaired?
Mistakes to avoid Taking 3 d 3d 3 d electrons off before 4 s 4s 4 s when forming an ion. Letting l l l equal n n n . It must be smaller. Pairing electrons too early. Hund's rule spreads them out first. Counting orbitals as electrons. Each orbital holds two. Check yourself What is the de Broglie wavelength of an electron moving at 1.0 × 10 7 m s − 1 1.0 \times 10^{7}\ \text{m s}^{-1} 1.0 × 1 0 7 m s − 1 ? Stuck? Show a hint Show the answerHow many orbitals are there in a d d d subshell? Stuck? Show a hint Show the answerWrite the configuration of calcium, Z = 20 Z = 20 Z = 20 . Stuck? Show a hint Show the answerWhich principle limits an orbital to two electrons? Stuck? Show a hint Show the answer