Experiments with Circuits, Lenses and Diodes: Quick Revision
A brief note on Experiments with Circuits, Lenses and Diodes: Ohm's law, the metre bridge, the potentiometer, a galvanometer made into meters, the diode, and the lens, slab and prism, with formulas, practice and questions to check yourself.
A brief note on Experiments with Circuits, Lenses and Diodes. Read it before a practical examination. Try each question at the end before you open its answer.
Circuits
Ohm's law: the graph of V against I is a line through the origin with the slope R. ρ=4lRπd2. The ammeter is in series. The voltmeter is across the wire alone.
Metre bridge:SR=100−ll. The error is least near l=50 cm. Interchange R and S to remove end errors.
Potentiometer:V=kl. E2E1=l2l1 and r=Rl2l1−l2. The driver emf is larger than the test emf.
Galvanometer:G=R−SRS. Ammeter: S=I−IgIgG in parallel. Voltmeter: R=IgV−G in series.
Diode: the knee is near 0.7 V (silicon) and 0.3 V (germanium). rd=ΔIΔV. Use a series resistor in forward bias.
Light
Lens and mirror:f1=u1+v1. The graph of v1 against u1 cuts both axes at f1. Displacement method: f=4DD2−d2.
Slab:n=sinrsini. Lateral shift d=cosrtsin(i−r).
Prism:n=sin2Asin2A+δm. At δm, i=e.
A worked example
A galvanometer of 75Ω gives full deflection for 400μA. Make it a voltmeter of 5.0 V.
The total resistance.IgV=400×10−6A5.0V=12500Ω.
The series resistor.R=12500Ω−75Ω=12425Ω.
Practise with new numbers
Check yourself
A metre bridge balances at 60.0 cm with a known resistance of 8.0Ω in the right gap. What is the unknown resistance?
Why is the dynamic resistance of a diode not equal to V/I?
A prism has an angle of 60∘. At the least deviation, the angle of incidence is 50∘. What is the least deviation?
Sources
NCERT, Laboratory Manual: Physics, Class XII.
NCERT, Physics Class XII, Chapters 3, 4, 9 and 14.