Cutting a chain with ozone

A straight-chain hydrocarbon has more than one double bond. Ozone cuts every one of them. You will count what forms.

The idea. Each double bond is cut into two C=O groups. A chain with $d$ double bonds is cut into $d + 1$ pieces. Each double bond uses one molecule of ozone.

Your tasks.

1. Set ozone to the moles of ozone that one mole of the hydrocarbon uses.
2. Set carbonyls to the number of C=O groups in all the products, counted for one molecule.
3. Set pieces to the number of molecules the chain is cut into.
4. Set left_piece to the number of carbon atoms in the left-hand piece when the first double bond sits between carbon first and carbon first + 1.