Carbon bookkeeping for three preparations

A sodium salt of a carboxylic acid and an alkyl halide are the starting materials. You will find how many carbon atoms each preparation puts into its alkane.

The idea. Soda lime takes the carboxyl carbon away. Kolbe electrolysis joins two alkyl groups, each without its carboxyl carbon. The Wurtz reaction joins two halide chains. An alkane has $2n + 2$ hydrogen atoms for $n$ carbon atoms.

Your tasks.

1. Set soda_lime to the number of carbon atoms in the alkane made by heating the salt with soda lime.
2. Set kolbe to the number made by Kolbe electrolysis of the salt.
3. Set wurtz to the number made by the Wurtz reaction of the halide.
4. Set hydrogens to the number of hydrogen atoms in the alkane of the Wurtz reaction.