Course 2.3Lesson 2 of 3
The standard deviation tells us how far a typical value is from the mean. Find each distance from the mean, square it, find the mean of the squares, which is the variance, then take the square root. It is in the same units as the data. A small standard deviation means the values are close to the mean, and zero means they are all equal.
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The range and the IQR look at a few values. The standard deviation uses every value. It asks: how far is a typical value from the mean?
We could find the distance of each value from the mean and take the average. But the distances below the mean are negative and those above are positive, so they cancel. In Course 3.1 you saw that they always add up to .
The fix is to square each distance. A square is never negative.
The Greek letter , sigma, is the standard deviation, and is the mean. The square root in step 5 puts the answer back in the same units as the data.
You should find that a value far from the mean gives a very tall bar, because squaring makes large distances count much more. Put all five values together, and every bar, and the variance, drop to zero.
Here we divide by , the number of values, because we have all the data. When the data is only a sample of a bigger group, a second version divides by . You will meet it in the next stage. The idea is the same.
Try each one on your own first. If you are stuck, open a hint. Then check with Show the answer.
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