Formulas and Stoichiometry

Name: Formulas and Stoichiometry
Author: StemPy Lab

Find a compound's formula from its percentage composition, work out how much of each substance a reaction needs and makes, find the limiting reagent, and express the strength of a solution.

3 lessons, about 1 h 20 min3 simulations12 problems6 practice questionsPython in every lesson

Created by StemPy Lab

Course outline (3 lessons)

Lesson 1about 30 min
Percentage composition and formulas
A compound always has the same composition by mass. The mass percent of an element is its share of the molar mass. From the percentages we find the empirical formula, the simplest whole-number ratio of the atoms. The molar mass then gives the molecular formula.
1 simulation2 practice questions1 Python program4 problems1 Python lab
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Lesson 2about 25 min
Stoichiometry and the limiting reagent
A balanced equation gives the ratio of the reacting amounts in moles. From it we work out masses and gas volumes: mass to moles, moles by the mole ratio, then moles to mass. The reactant that runs out first is the limiting reagent, and it decides how much product forms.
1 simulation2 practice questions1 Python program4 problems1 Python lab
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Lesson 3about 25 min
Concentration of solutions
A solution has a solute dissolved in a solvent. Its strength can be given as a mass percent, a mole fraction, a molarity (moles per litre of solution) or a molality (moles per kilogram of solvent). Molality does not change with temperature, because it uses masses only.
1 simulation2 practice questions1 Python program4 problems1 question set1 note
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Stoichiometry: NEET Style Test

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← Some Basic Concepts of Chemistry

← Laws, Atoms and the MoleNext →

More onAtoms and Molecules › Stoichiometry and Concentration Atoms and Molecules › The Mole Concept Atoms and Molecules › Molecules, Ions and Formulae

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Formulas and Stoichiometry

Course outline (3 lessons)

Percentage composition and formulas

Stoichiometry and the limiting reagent

Concentration of solutions

Test Your Learning

Your teacher

Discussion (0)

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