Stoichiometry and the limiting reagent · Chemistry Class 11–12 | StemPy Lab
Course 1.3·Lesson 2 of 3
Stoichiometry and the limiting reagent
A balanced equation gives the ratio of the reacting amounts in moles. From it we work out masses and gas volumes: mass to moles, moles by the mole ratio, then moles to mass. The reactant that runs out first is the limiting reagent, and it decides how much product forms.
about 25 min1 simulation2 practice questions
Lesson 2 of 3Show all lessonsHide
Try the code and the simulations beside the lesson.
What a balanced equation says
LPG, the gas in a kitchen cylinder, is mostly propane. It burns like this:
C3H8+5O2→3CO2+4H2O
The same equation can be read in four ways.
Molecules. One molecule of propane reacts with five molecules of oxygen. They give three molecules of carbon dioxide and four of water.
Moles.1mol+5mol→3mol+4mol.
Masses.44g+160g→132g+72g. Both sides add up to 204g, so mass is conserved.
Gas volumes. At the same temperature and pressure, equal moles of gases fill equal volumes. At STP (273.15K and 1bar), one mole of any gas fills 22.7L.
The coefficients give the mole ratio. Working out amounts from this ratio is called stoichiometry.
Mass to mass in three steps
A balanced equation links moles, never grams. So every problem goes through moles.
Mass to moles. Divide the mass by the molar mass.
Moles to moles. Multiply by the mole ratio from the equation.
Moles to mass. Multiply by the molar mass of the substance you want, or by 22.7L for a gas at STP.
Example. How much carbon dioxide forms when 22g of propane burns, and how much oxygen does it use?
Propane: 4422=0.5mol.
Carbon dioxide: 0.5×3=1.5mol, which is 1.5×44=66g, or 1.5×22.7=34.05L at STP.
Oxygen: 0.5×5=2.5mol, which is 2.5×32=80g.
The limiting reagent
A sandwich needs 2 slices of bread and 1 slice of cheese. With 10 slices of bread and 4 of cheese, you can make only 4 sandwiches, and 2 slices of bread are left. The cheese limits the number of sandwiches.
In a reaction, the reactant that is used up first is the limiting reagent. It decides how much product forms. The other reactant is in excess, and some of it is left over.
Example.56g of nitrogen and 9g of hydrogen react: N2+3H2→2NH3.
Divide each by its coefficient. Nitrogen: 12=2. Hydrogen: 34.5=1.5. The smaller share belongs to hydrogen, so hydrogen is the limiting reagent.
Product. Ammonia: 32×4.5=3mol, which is 3×17=51g.
Excess. Nitrogen used: 1.5mol. Left over: 0.5mol, which is 14g.
Check. At the start, 56+9=65g. At the end, 51+14=65g.
Practise with new numbers
Try it in Python
Aluminium burns in chlorine: 2Al+3Cl2→2AlCl3. The program finds the limiting reagent, the product and what is left over.
Common mistakes
Using an equation that is not balanced. The mole ratio comes from the coefficients, so balance first.
Using a mass ratio. The equation gives moles. 1g of nitrogen does not react with 3g of hydrogen.
Choosing the limiting reagent by its mass, or by its moles alone. Divide the moles by the coefficient, then compare.
Forgetting the excess. The reactant in excess is not all used. Work out what is left.
Remember these
The coefficients of a balanced equation give the mole ratio.
Mass problems go mass to moles, moles to moles, moles to mass.
At STP, one mole of a gas fills 22.7L. Equal moles of gases fill equal volumes.
The limiting reagent has the smallest value of moles divided by its coefficient. It fixes the amount of product.
Check yourself
Try each one on your own first. If you are stuck, open a hint. Then check with Show the answer.
In the burning of propane, C3H8+5O2→3CO2+4H2O, how many moles of oxygen does 2 mol of propane need?
Magnesium burns: 2Mg+O2→2MgO. What mass of magnesium oxide comes from 12g of magnesium? Use Mg=24 and O=16.
Riya has 6 slices of bread and 5 slices of cheese. A sandwich needs 2 slices of bread and 1 of cheese. How many sandwiches can she make, and what is left?
1 mol of nitrogen and 1 mol of hydrogen are mixed to make ammonia. Which is the limiting reagent?
What volume does 0.5 mol of oxygen gas fill at STP?
Enroll free in Formulas and Stoichiometry
Every lesson is open to read. Enrolling also lets you:
Mark lessons done and carry on where you stopped.
Take the tests of this lesson and its course.
Count the course towards the certificate for its chapter.