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The potential energy of a particle moving along a line… | StemPy Lab
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The potential energy of a particle moving along a line is U(r) = a/r² - b/r for r > 0, where a and b are positive constants. The particle can be in equilibrium at
Physics
Hard
High School (11–12)
Mechanics › Work, Energy and Power
JEE Main
Created by
StemPy Lab
The potential energy of a particle moving along a line is
U
(
r
)
=
a
r
2
−
b
r
U(r) = \dfrac{a}{r^2} - \dfrac{b}{r}
U
(
r
)
=
r
2
a
−
r
b
for
r
>
0
r > 0
r
>
0
, where
a
a
a
and
b
b
b
are positive constants. The particle can be in equilibrium at
r
=
a
b
r = \dfrac{a}{b}
r
=
b
a
, and the equilibrium is stable
r
=
a
2
b
r = \dfrac{a}{2b}
r
=
2
b
a
, and the equilibrium is unstable
r
=
2
a
b
r = \dfrac{2a}{b}
r
=
b
2
a
, and the equilibrium is stable
r
=
2
a
b
r = \dfrac{2a}{b}
r
=
b
2
a
, and the equilibrium is unstable
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