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The osmotic pressure of a solution of 0.54 g of a… | StemPy Lab
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The osmotic pressure of a solution of 0.54 g of a polymer in 180 mL of solution is 0.15 kPa at 27 °C. What is the molar mass of the polymer? Take R = 8.314 J K⁻¹mol⁻¹.
Chemistry
Hard
High School (11–12)
Solutions › Colligative Properties and the van 't Hoff Factor
NEET
AP
Created by
StemPy Lab
The osmotic pressure of a solution of
0.54
g
0.54\ \text{g}
0.54
g
of a polymer in
180
mL
180\ \text{mL}
180
mL
of solution is
0.15
kPa
0.15\ \text{kPa}
0.15
kPa
at
27
∘
C
27\ ^\circ\text{C}
27
∘
C
. What is the molar mass of the polymer? Take
R
=
8.314
J K
−
1
mol
−
1
R = 8.314\ \text{J K}^{-1}\text{mol}^{-1}
R
=
8.314
J K
−
1
mol
−
1
.
5.0
×
10
7
g/mol
5.0 \times 10^{7}\ \text{g/mol}
5.0
×
1
0
7
g/mol
5.0
×
10
4
g/mol
5.0 \times 10^{4}\ \text{g/mol}
5.0
×
1
0
4
g/mol
4.9
×
10
2
g/mol
4.9 \times 10^{2}\ \text{g/mol}
4.9
×
1
0
2
g/mol
5.0
×
10
1
g/mol
5.0 \times 10^{1}\ \text{g/mol}
5.0
×
1
0
1
g/mol
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Solutions › Colligative Properties and the van 't Hoff Factor
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