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The normal form of √3 x + y - 8 = 0 is | StemPy Lab
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The normal form of √3 x + y - 8 = 0 is
Mathematics
Medium
High School (11–12)
Coordinate Geometry › Straight Lines
SAT
A-Level
IB
Created by
StemPy Lab
The normal form of
3
x
+
y
−
8
=
0
\sqrt{3}\,x + y - 8 = 0
3
x
+
y
−
8
=
0
is
x
cos
60
∘
+
y
sin
60
∘
=
4
x\cos 60^\circ + y\sin 60^\circ = 4
x
cos
6
0
∘
+
y
sin
6
0
∘
=
4
x
cos
30
∘
−
y
sin
30
∘
=
4
x\cos 30^\circ - y\sin 30^\circ = 4
x
cos
3
0
∘
−
y
sin
3
0
∘
=
4
x
cos
30
∘
+
y
sin
30
∘
=
4
x\cos 30^\circ + y\sin 30^\circ = 4
x
cos
3
0
∘
+
y
sin
3
0
∘
=
4
x
cos
30
∘
+
y
sin
30
∘
=
8
x\cos 30^\circ + y\sin 30^\circ = 8
x
cos
3
0
∘
+
y
sin
3
0
∘
=
8
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