The origin is moved to the point (3, -2)…

The lines through the meeting point of $L_1 = 0$ and $L_2 = 0$ are $L_1 + kL_2 = 0$, except $L_2$ itself. To find the fixed point of a family with a letter $k$, collect the terms with $k$ and solve the two brackets together. Three lines are concurrent when the meeting point of two lies on the third. Shifting the origin to $(h, k)$ puts $x = X + h$ and $y = Y + k$.