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The function f(x) = x/(x² + 1) has derivative f'(x) =… | StemPy Lab
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The function f(x) = x/(x² + 1) has derivative f'(x) = (1 - x²)/((x² + 1)²). On which interval is f strictly increasing?
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Functions and Calculus › Application of Derivatives
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The function
f
(
x
)
=
x
x
2
+
1
f(x) = \dfrac{x}{x^2 + 1}
f
(
x
)
=
x
2
+
1
x
has derivative
f
′
(
x
)
=
1
−
x
2
(
x
2
+
1
)
2
f'(x) = \dfrac{1 - x^2}{(x^2 + 1)^2}
f
′
(
x
)
=
(
x
2
+
1
)
2
1
−
x
2
. On which interval is
f
f
f
strictly increasing?
(
−
1
,
1
)
(-1, 1)
(
−
1
,
1
)
(
−
∞
,
0
)
(-\infty, 0)
(
−
∞
,
0
)
(
0
,
∞
)
(0, \infty)
(
0
,
∞
)
(
−
∞
,
−
1
)
∪
(
1
,
∞
)
(-\infty, -1) \cup (1, \infty)
(
−
∞
,
−
1
)
∪
(
1
,
∞
)
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