ChemistryAdvancedHigh School (11–12)Organic Chemistry: Some Basic Principles and Techniques › Electronic Effects and Reaction IntermediatesNEETJEE Main
Created by StemPy LabThe figure shows four carbocations, I to IV, drawn as bond-line formulas. Their stability depends on how many alkyl groups the positive carbon carries, through the inductive effect and hyperconjugation. Which option gives the order of stability, from the most stable to the least stable, and the number of bonds that can take part in hyperconjugation in the most stable ion?
← All Quizzes
← In 1-chloropropane, CH₃CH₂CH₂Cl, the carbon-chlorine bond is polar. A student writes two statements about how this polarity spreads along the chain. Statement I: The carbon bonded to chlorine carries a partial positive charge; the next carbon carries a smaller one, and the effect becomes almost nothing after three bonds. Statement II: The electromeric effect also works in 1-chloropropane at all times, because its carbon-chlorine bond is permanently polarised.Match each displacement of electrons in List-I with the effect in List-II. List-I (Situation) A. The nitrogen lone pair of aniline is delocalised into the ring B. The ring π electrons of nitrobenzene are drawn towards the nitro group C. H⁺ attacks ethene, and the π electrons move to the carbon that takes the H⁺ D. CN⁻ attacks the carbon of a C=O group, and the π electrons move to the oxygen List-II (Effect) I. -E effect II. +R effect III. -R effect IV. +E effect →
Discussion (0)
Log in to join the discussion.
Loading…