Match each cell in List-I, at $298\ \text{K}$, with its emf in List-II. Each emf is for the cell as written, with the left electrode as the anode, so a negative value means the cell really runs the other way. Use NCERT's values: $E^\circ(\text{Mg}^{2+}/\text{Mg}) = -2.36\ \text{V}$, $E^\circ(\text{Ag}^+/\text{Ag}) = 0.80\ \text{V}$, $E^\circ(\text{Sn}^{2+}/\text{Sn}) = -0.14\ \text{V}$ and $E^\circ(\text{Pb}^{2+}/\text{Pb}) = -0.13\ \text{V}$, with $\dfrac{2.303RT}{F} = 0.059\ \text{V}$. Concentrations are in $\text{mol L}^{-1}$. In every cell the solutions behave ideally, and each gas is at the pressure shown. List-I (P) $\text{Mg}\,|\,\text{Mg}^{2+}(0.0010)\,\|\,\text{Ag}^+(0.100)\,|\,\text{Ag}$ (Q) $\text{Pt}\,|\,\text{H}_2(1\ \text{bar})\,|\,\text{H}^+(\text{pH}\ 3.00)\,\|\,\text{H}^+(\text{pH}\ 1.00)\,|\,\text{H}_2(1\ \text{bar})\,|\,\text{Pt}$ (R) $\text{Sn}\,|\,\text{Sn}^{2+}(1.00)\,\|\,\text{Pb}^{2+}(0.0010)\,|\,\text{Pb}$ (S) $\text{Cu}\,|\,\text{Cu}^{2+}(0.0100)\,\|\,\text{Cu}^{2+}(1.00)\,|\,\text{Cu}$ List-II (1) $0.06\ \text{V}$ (2) $3.19\ \text{V}$ (3) $-0.08\ \text{V}$ (4) $0.12\ \text{V}$ (5) $0.10\ \text{V}$