For C₃H₈ + 5O₂ → 3CO₂ + 4H₂O, the program finds 0.45…

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For $\text{C}_3\text{H}_8 + 5\text{O}_2 \rightarrow 3\text{CO}_2 + 4\text{H}_2\text{O}$ , the program finds $0.45$ rounds for propane and $0.15$ for oxygen. How many moles of water form?

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← The pairs of ethanol, C2H5OH, are counted. What does this print? c = {}; for el, n in [("C", "2"), ("H", "5"), ("O", ""), ("H", "")]:; c[el] = c.get(el, 0) + int(n or 1); print(c)A student writes rounds = {s: moles[s] * coef[s] for s in coef}. What goes wrong? →

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