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For 2NO₂(g) ⇌ N₂O₄(g), Kc = 170 at a certain… | StemPy Lab
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For 2NO₂(g) ⇌ N₂O₄(g), Kc = 170 at a certain temperature. A flask at that temperature holds [NO₂] = 0.12 mol/L and [N₂O₄] = 1.73 mol/L. Which is right?
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Equilibrium › Chemical Equilibrium
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Created by
StemPy Lab
For
2
NO
2
(g)
⇌
N
2
O
4
(g)
2\text{NO}_2\text{(g)} \rightleftharpoons \text{N}_2\text{O}_4\text{(g)}
2
NO
2
(g)
⇌
N
2
O
4
(g)
,
K
c
=
170
K_c = 170
K
c
=
170
at a certain temperature. A flask at that temperature holds
[
NO
2
]
=
0.12
[\text{NO}_2] = 0.12
[
NO
2
]
=
0.12
mol/L and
[
N
2
O
4
]
=
1.73
[\text{N}_2\text{O}_4] = 1.73
[
N
2
O
4
]
=
1.73
mol/L. Which is right?
Q
c
=
120
Q_c = 120
Q
c
=
120
, so more
NO
2
\text{NO}_2
NO
2
forms
Q
c
=
120
Q_c = 120
Q
c
=
120
, so more
N
2
O
4
\text{N}_2\text{O}_4
N
2
O
4
forms
Q
c
=
170
Q_c = 170
Q
c
=
170
, so the mixture is at equilibrium
Q
c
=
14.4
Q_c = 14.4
Q
c
=
14.4
, so more
N
2
O
4
\text{N}_2\text{O}_4
N
2
O
4
forms
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