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For PCl₅(g) ⇌ PCl₃(g) + Cl₂(g), Kc = 0.040 at 600 K… | StemPy Lab

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For PCl₅(g) ⇌ PCl₃(g) + Cl₂(g), Kc = 0.040 at 600 K. Taking R = 0.0831 L bar/(K mol), what is Kp?

ChemistryMediumHigh School (11–12)Equilibrium › Chemical Equilibrium A-Level AEEE (Amrita)AMUEEE AP AP EAPCET BCECE COMEDK UGET GUJCET IB JCECE JKCET KCET KEAM KIITEE LPUNEST MET (Manipal)MHT-CET NEET OJEE SRMJEEE TS EAPCET UPESEAT VITEEE

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For $\text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g)$ , $K_c = 0.040$ at $600\ \text{K}$ . Taking $R = 0.0831\ \text{L bar/(K mol)}$ , what is $K_p$ ?

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← A reaction in a closed vessel has reached equilibrium. Which statement is true?The Haber process gives out heat and turns four moles of gas into two. Which change raises the share of ammonia at equilibrium? →

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