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Copper(II) ions oxidise iodide ions: 2Cu²⁺ + 4I⁻ → 2CuI… | StemPy Lab
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Copper(II) ions oxidise iodide ions: 2Cu²⁺ + 4I⁻ → 2CuI + I₂. The iodine released needs 24.5 mL of 0.0400 mol/L thiosulfate, by I₂ + 2S₂O₃²⁻ → 2I⁻ + S₄O₆²⁻. How many moles of copper(II) were in the sample?
Chemistry
Hard
High School (11–12)
Redox Reactions › Balancing Redox Equations and Redox Titrations
JEE Main
AP
A-Level
IB
Created by
StemPy Lab
Copper(II) ions oxidise iodide ions:
2
Cu
2
+
+
4
I
−
→
2
CuI
+
I
2
2\text{Cu}^{2+} + 4\text{I}^- \rightarrow 2\text{CuI} + \text{I}_2
2
Cu
2
+
+
4
I
−
→
2
CuI
+
I
2
. The iodine released needs
24.5
mL
24.5\ \text{mL}
24.5
mL
of
0.0400
mol/L
0.0400\ \text{mol/L}
0.0400
mol/L
thiosulfate, by
I
2
+
2
S
2
O
3
2
−
→
2
I
−
+
S
4
O
6
2
−
\text{I}_2 + 2\text{S}_2\text{O}_3^{2-} \rightarrow 2\text{I}^- + \text{S}_4\text{O}_6^{2-}
I
2
+
2
S
2
O
3
2
−
→
2
I
−
+
S
4
O
6
2
−
. How many moles of copper(II) were in the sample?
3.92
×
10
−
3
mol
3.92 \times 10^{-3}\ \text{mol}
3.92
×
1
0
−
3
mol
1.96
×
10
−
3
mol
1.96 \times 10^{-3}\ \text{mol}
1.96
×
1
0
−
3
mol
9.80
×
10
−
4
mol
9.80 \times 10^{-4}\ \text{mol}
9.80
×
1
0
−
4
mol
4.90
×
10
−
4
mol
4.90 \times 10^{-4}\ \text{mol}
4.90
×
1
0
−
4
mol
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Redox Reactions › Balancing Redox Equations and Redox Titrations
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