Assertion (A): A student adds HI to propene, $\text{CH}_3\text{CH}=\text{CH}_2$, in the presence of benzoyl peroxide, expecting the same peroxide effect as with HBr. The main product is 1-iodopropane, $\text{CH}_3\text{CH}_2\text{CH}_2\text{I}$, formed against Markovnikov's rule. Reason (R): The $\text{H}-\text{I}$ bond, with a bond enthalpy of $296.8\ \text{kJ mol}^{-1}$, is weaker than the $\text{H}-\text{Br}$ bond, $363.7\ \text{kJ mol}^{-1}$, while the $\text{H}-\text{Cl}$ bond, $430.5\ \text{kJ mol}^{-1}$, is the strongest of the three.