Created by StemPy LabFour alkenes are warmed separately with acidic , which breaks the double bond. A chemist uses such products to find where the double bond sits in an unknown alkene. Match each alkene with its products. List-I (Alkene) A. But-1-ene B. But-2-ene C. 2-Methylpropene D. 2-Methylbut-2-ene List-II (Products) I. and II. only III. and IV. and
← All Quizzes
← The figure shows 2-methylpropene and four reactions of it, A to D, each with the reagents over its arrow. Each reaction gives one main product that keeps the four carbon skeleton. Match each reaction with its main product.
List-I (Reaction in the figure)
A. Reaction A
B. Reaction B
C. Reaction C
D. Reaction D
List-II (Main product)
I. 2-chloro-2-methylpropane
II. 2-bromo-2-methylpropane
III. 2-methylpropan-2-ol
IV. 1-bromo-2-methylpropaneSix statements about the acidic character of hydrocarbons are given below. (i) The acidic character falls as HC≡CH > CH₃C≡CH ≫ CH₂=CH₂ > CH₃CH₃. (ii) Ethyne reacts with sodium metal and gives monosodium ethynide and dihydrogen. (iii) All four hydrogen atoms of propyne, CH₃C≡CH, are acidic. (iv) But-2-yne reacts with sodamide and gives ammonia. (v) An sp carbon, with 50% s character, is more electronegative than an sp² or sp³ carbon. (vi) Ethene is more acidic than ethyne, because its π bond is weaker. How many of the statements above are correct? →
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