PhysicsAdvancedHigh School (11–12)Electricity & Magnetism › Electric Potential and CapacitanceJEE Advanced
Created by StemPy LabA parallel-plate capacitor with air between its plates is charged to a potential difference by a battery. Each change in List I starts again from this state. "Battery on" means the battery stays connected; "battery off" means it is removed first. A slab, where used, has dielectric constant , covers the plates fully and fills half the gap. Match each change with the factor by which the total energy stored in the capacitors changes. List I (P) Battery on: the plates are pulled apart to twice the gap. (Q) Battery off: the slab is slid in. (R) Battery on: the slab is slid in. (S) Battery off: the capacitor is joined across an uncharged capacitor . List II (1) ; (2) ; (3) ; (4) ; (5) . Which matching is correct?
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← The two square plates of a capacitor, each 10 cm by 10 cm, are not quite parallel. Along one edge they are 1.0 mm apart, and the gap grows steadily to 3.0 mm along the opposite edge, as in the figure. There is air between them. The tilt is small, so treat each narrow strip of the plates, parallel to those edges, as a small parallel-plate capacitor of its own gap. The plates are joined to nothing else, and the effects at the edges can be ignored. Take ε₀ = 8.85 × 10⁻¹² C² N⁻¹ m⁻². What is the capacitance?A parallel-plate capacitor has plates of area 100 cm², 6.0 mm apart, and a 120 V battery stays connected across it. An uncharged metal slab 2.0 mm thick, as large as the plates, is held inside on insulating supports, parallel to the plates. It is 1.0 mm from the positive plate and 3.0 mm from the negative plate, as in the figure. The supports carry no charge, and the slab touches neither plate. Ignore the effects at the edges. Take ε₀ = 8.85 × 10⁻¹² C² N⁻¹ m⁻². Which of the following statements are correct? →
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