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A group of 10 students has a standard deviation of 4… | StemPy Lab
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A group of 10 students has a standard deviation of 4 marks and a group of 30 students has a standard deviation of 8 marks. A student says that the standard deviation of all 40 is (10 × 4 + 30 × 8)/40 = 7 marks. What is wrong with this?
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Statistics and Probability › Statistics
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A group of
10
10
10
students has a standard deviation of
4
4
4
marks and a group of
30
30
30
students has a standard deviation of
8
8
8
marks. A student says that the standard deviation of all
40
40
40
is
10
×
4
+
30
×
8
40
=
7
\dfrac{10 \times 4 + 30 \times 8}{40} = 7
40
10
×
4
+
30
×
8
=
7
marks. What is wrong with this?
The standard deviations should be added, not averaged
The group of
30
30
30
should not be counted
There is nothing wrong, because the combined mean is also a weighted mean
It ignores how far the two group means are from the combined mean
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