Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Two octahedral complexes of () have measured magnetic moments of and . Use and round to the nearest whole number. Find the number of unpaired electrons in each. Then find the number of electrons in the set in the second one.
Total energy . Octahedral: . Tetrahedral: , with . and .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The first. , so , which rounds to 4.
Step 2. The second. , so , which rounds to 2.
Step 3. What the numbers mean. Four unpaired electrons is , high spin. Two unpaired electrons is , low spin: the fourth electron paired up in , so 4 electrons sit in .
Check. , close to the measured . The small excess comes from orbital motion.
Answer: 4, 2 and 4. The second complex has the stronger ligand.
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