A ball is kicked at 30 m/s, at 30° above a level field…

Step 1. Split. $u_x = 30\ \text{m/s}\cos 30^\circ = 26.0\ \text{m/s}$ and $u_y = 30\ \text{m/s}\sin 30^\circ = 15\ \text{m/s}$.

Step 2. Time. $T = \dfrac{2u_y}{g} = \dfrac{2 \times 15\ \text{m/s}}{9.8\ \text{m/s}^2} = 3.06\ \text{s}$.

Step 3. Height. $H = \dfrac{u_y^2}{2g} = \dfrac{(15\ \text{m/s})^2}{2 \times 9.8\ \text{m/s}^2} = 11.5\ \text{m}$.

Step 4. Range. $R = u_x T = 26.0\ \text{m/s} \times 3.06\ \text{s} = 79.5\ \text{m}$.