A 3.5 kg block rests on a smooth floor. A steady horizontal pull of 12 N drags it 6.0 m…

Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

A $3.5\ \text{kg}$ block rests on a smooth floor. A steady horizontal pull of $12\ \text{N}$ drags it $6.0\ \text{m}$ . How fast is it moving at the end?

Need a reminder? The key ideaShow

Kinetic energy is $K = \tfrac12 mv^2$ . The work-energy theorem: the net work done on a body equals its change in kinetic energy, $W_{\text{net}} = \tfrac12 mv^2 - \tfrac12 mu^2$ .

The worked solution

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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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