Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
The van der Waals equation for carbon dioxide, and , gives an S-shaped isotherm at . The loop spans pressures from to . Use the equal area construction to find the pressure at which gas and liquid exist together at this temperature, according to the equation. Give the molar volume of the liquid and the molar volume of the gas at that pressure. The critical temperature of the model is .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. , , .
Step 1. The idea. The equation of van der Waals gives a loop below , which is not real. The true isotherm replaces the loop with a horizontal line at the vapour pressure. The line is placed so that the area of the loop above the line equals the area below it.
Step 2. The search. For each pressure between and , solve the cubic . Take the lowest and the highest root. Add up the area between the curve and the line. The area is zero at .
Step 3. The volumes. At the lowest root is , the liquid, and the highest is , the gas. The middle root is not stable.
Check. The equation is a model. The measured vapour pressure of carbon dioxide at is lower than , so the model overstates it. It still shows a liquid and a gas side by side, which the ideal gas equation cannot do.
Answer: , with for the liquid and for the gas.
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. The van der Waals equation is . Its critical constants are , and . From and , and . The Boyle temperature is .