Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
The same charge passes through two cells in series. One holds silver nitrate and gains of silver. The other holds a salt of tin and gains of tin. Use and . Find the moles of electrons that passed, the moles of tin deposited, and the charge number of the tin ion.
, with the time in seconds, and . For , the mass is . The same charge through different cells gives masses in the ratio of . At and one mole of gas is .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Plan. Count the electrons from the silver. Count the tin. The ratio is .
Step 1. Electrons. , since each takes 1 electron.
Step 2. Tin. .
Step 3. The ratio. , so .
Answer: of electrons, of tin, and the ion is , so .
Watch out. A ratio that is not near a whole number would mean a mistake in the masses or the molar masses.
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