Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
The standard potential of the electrode , for , is . The standard potential of is . At , (a) find the solubility product of lead sulphate. (b) What is its solubility, in ? (c) What mass of lead sulphate, of molar mass , dissolves in a litre of water?
The hydrogen electrode at has , so with a reference electrode of potential the cell emf is . A glass electrode is calibrated with two buffers: the slope is the change in reading divided by the change in pH. For a silver halide, , and the same form holds for another metal with .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Plan. Solve the potential relation for . Then use .
Step 1. The solubility product. , so .
Step 2. The solubility. .
Step 3. The mass. in each litre.
Answer: , and in a litre.
Check. A solubility of about means a very sparingly soluble salt. The sulphate electrode potential is lower than that of , as it must be when the precipitate removes lead ions.
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