Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
The filling order would give palladium () the outer configuration . In fact palladium has no electron. Silver () has one. Find the number of electrons in and for palladium, and the number of unpaired electrons in a silver atom.
The d block is groups 3 to 12. A transition element has an incomplete d subshell, with 1 to 9 electrons, in its atom or in a common ion. The 3d series fills after , except Cr () and Cu (). An ion loses its electrons first, so an ion has electrons in once both electrons are gone. By Hund's rule, a subshell with electrons has unpaired electrons if and if .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. Palladium is a second-row exception to the filling order.
Step 1. Palladium. Moving both electrons into fills the subshell. The configuration is , with electrons in and in .
Step 2. Silver. The plain rule gives . One electron moves, so silver is .
Step 3. Unpaired electrons in silver. The subshell is full, so all its electrons are paired. The single electron is unpaired. So there is unpaired electron.
Answer: palladium has electrons in and in . A silver atom has unpaired electron.
Check. The same pattern appears in the third row, where gold is .
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