Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
An ion of the 3d series has the configuration . A different ion of the same series has five unpaired electrons. Find the atomic number of each element, and name them.
The d block is groups 3 to 12. A transition element has an incomplete d subshell, with 1 to 9 electrons, in its atom or in a common ion. The 3d series fills after , except Cr () and Cu (). An ion loses its electrons first, so an ion has electrons in once both electrons are gone. By Hund's rule, a subshell with electrons has unpaired electrons if and if .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Plan. Use and solve for .
Step 1. The 3+ ion. and , so . This is chromium.
Step 2. The 2+ ion. Five unpaired electrons need , one electron in each box. The six-electron case has only four unpaired. So . This is manganese.
Answer: (chromium) and (manganese).
Check. is and is . Both are well-known ions.
Log in to join the discussion.
Loading…