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25 mL of 0.05 mol/L sulphuric acid is titrated with 0.1 mol/L sodium hydroxide: H₂SO₄ + 2NaOH →…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
of sulphuric acid is titrated with sodium hydroxide: . At what volume of base is the end point? What does end_point(0.05, 25, 0.1) return without the ratio, and why is it wrong?
Need a reminder? The key ideaShow
Moles molarity . Dilution: . Mixing the same solute: add the moles and the volumes. At the end point of a titration, the moles of acid and base match the ratio of the equation.
The worked solution
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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Moles of acid. mmol.
Step 2. Base needed. mmol.
Step 3. Volume. .
Step 4. Without the ratio. end_point(0.05, 25, 0.1) returns 12.5, the volume for a acid. Pass ratio=2.
Answer: of base.
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