Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Ranjit belongs to an astronomy club, and the club owns a telescope with an objective of diameter . On a clear night he looks at the Moon in green light of wavelength , and he wants to know how small a feature he could ever hope to see there. The Moon is away. The pupil of the unaided eye is across, in the same light. His friend would like to compare the answer with the size of a town, so the sizes must be in metre. Find the smallest angle that the telescope can separate, in arcsecond. Find the smallest feature on the Moon that it can separate. Find how many times larger the smallest feature is for the unaided eye. Then explain why Ranjit cannot see a smaller feature by fitting an eyepiece of a shorter focal length, which would only make every image larger, and say what would help instead. Use and one arcsecond .
Astronomical telescope, normal adjustment: and length . The smallest angle that an aperture can separate is . The light gathered is proportional to .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. , , , pupil .
Plan. Find the angle. Multiply it by the distance of the Moon. Repeat for the pupil.
Step 1. The angle. . In arcsecond, arcsecond.
Step 2. The feature on the Moon. .
Step 3. The eye. The same formula with a pupil of gives and . The ratio of the features is . It is the ratio of the two diameters.
Answer: arcsecond, , and times.
Why an eyepiece of shorter focal length does not help. A stronger eyepiece makes the image bigger, but the limit comes from diffraction at the objective. The two blobs overlap before the eyepiece sees them. A larger objective helps, or a shorter wavelength.
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