Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Name the product at each electrode when these are electrolysed. (a) Molten magnesium chloride between graphite electrodes. (b) Aqueous zinc sulphate between platinum electrodes. (c) Aqueous potassium iodide between platinum electrodes. (d) Aqueous silver nitrate between silver electrodes. Use , and .
In an electrolytic cell the anode is joined to the positive terminal of the battery and oxidation happens there. The cathode is negative and reduction happens there. At the cathode the species with the higher reduction potential is reduced, and water is a rival at . At the anode the species with the lower potential is oxidised, and water is a rival at about . An active electrode can dissolve.
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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
(a) Molten magnesium chloride. There is no water, so only and are present. Magnesium forms at the cathode and chlorine at the anode.
(b) Aqueous zinc sulphate. At the cathode, has , which is above water's , so zinc deposits. At the anode, sulphate is not oxidised, so water gives oxygen.
(c) Aqueous potassium iodide. At the cathode, is far below water, so hydrogen forms. At the anode, iodide has , below water's , so iodine forms. The solution around the cathode becomes alkaline.
(d) Aqueous silver nitrate, silver electrodes. Silver deposits at the cathode, because is high. The silver anode is active and has a low potential, so the anode itself dissolves: . Nothing is made from water.
Answer: (a) Mg and ; (b) Zn and ; (c) and ; (d) Ag deposits and the Ag anode dissolves.
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