Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Lithium fluoride and sodium bromide can be studied as single molecules in a hot gas. LiF has a dipole moment of and a bond length of . NaBr has and . Find the percent ionic character of each bond. Which is more ionic, and does that fit Fajans' rules?
Percent ionic character . A charge at gives , and .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. LiF. Full charges: . Ionic character: .
Step 2. NaBr. Full charges: . Ionic character: .
Step 3. Compare. LiF is more ionic. The small fluoride ion is hard to pull out of shape, while the large bromide ion is easily polarised. That fits Fajans' rules, even though is the smaller cation.
Answer: LiF , NaBr ; LiF is more ionic.
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