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Zinc reacts with excess hydrochloric acid: Zn + 2HCl → ZnCl₂ + H₂…

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Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

Zinc reacts with excess hydrochloric acid: $\text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2$ . What volume of hydrogen at STP comes from $13.0\ \text{g}$ of zinc? Use Zn $= 65.38$ g/mol and $22.7\ \text{L}$ for each mole of gas.

Need a reminder? The key ideaShow

Rounds of the equation for a reactant $= \dfrac{\text{moles}}{\text{coefficient}}$ . The smallest is the extent, and its reactant is limiting. Products: extent $\times$ coefficient. Excess left: moles $-$ extent $\times$ coefficient. Percent yield $= \dfrac{\text{actual}}{\text{theoretical}} \times 100$ . At STP a mole of gas fills $22.7\ \text{L}$ .

The worked solution

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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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