Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Four joints of a steel frame have the coordinates , , and , in metres. The designer wants the four joints in one flat plane, so that a single panel can cover them. Find the value of for which this holds.
is the determinant of the three vectors. The parallelepiped has volume and the tetrahedron has of that. The product is zero when the vectors are coplanar.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The vectors. , and .
Step 2. The determinant. $
= 1\big[-(\lambda - 3) - 0\big] - 2\big[-(\lambda - 3) + 2\big] + 2\big[0 + 1\big]$.
Step 3. Simplify. .
Step 4. Solve. , so .
Check. For , , and . So is a combination of the other two edges, and the four points are coplanar.
Answer: .
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