A tent is a tetrahedron with the corners P(1, 0, 0), Q(0, 2, 0), R(0, 0, 3) and S(1, 1, 1), with…

Step 1. The edges. $\overrightarrow{PQ} = (-1, 2, 0)$, $\overrightarrow{PR} = (-1, 0, 3)$ and $\overrightarrow{PS} = (0, 1, 1)$.

Step 2. The volume. The determinant is $-1(0 - 3) - 2(-1 - 0) + 0 = 3 + 2 = 5$. The volume is $\dfrac{5}{6} \approx 0.83$ cubic metres.

Step 3. The base. $\overrightarrow{PQ}\times\overrightarrow{PR} = (6, 3, 2)$ with size $7$. The area of $PQR$ is $3.5$ square metres.

Step 4. The height. $V = \dfrac{1}{3}\times\text{base}\times h$, so $h = \dfrac{3 \times 5/6}{3.5} = \dfrac{5}{7} \approx 0.71$ metres.