Four flowers differ in their stamens. In flower P the stamens are joined to the petals…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
Four flowers differ in their stamens. In flower P the stamens are joined to the petals. In flower Q they are joined to the tepals. In flower R nine are joined into a tube and one is free. In flower S all are joined into one bundle. Name each condition.
Need a reminder? The key ideaShow
Fabaceae: zygomorphic flower, papilionaceous corolla (standard, two wings, a keel of two joined petals), ten stamens with nine joined and one free, one carpel, a legume, root nodules. Solanaceae: radial flower, united sepals and petals, five epipetalous stamens, two joined carpels, a berry or a capsule. Liliaceae: a monocot, six tepals in two whorls, six epiphyllous stamens, three joined carpels, a capsule.
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Flower P. Stamens joined to petals are epipetalous.
Step 2. Flower Q. Stamens joined to tepals are epiphyllous.
Step 3. Flower R. Two groups, nine joined and one free, are diadelphous.
Step 4. Flower S. One bundle is monadelphous.
Answer: P epipetalous, Q epiphyllous, R diadelphous, S monadelphous.
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