Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A school garden has pea plants, potato plants and lily plants. Each plant bears flowers. A pea flower has stamens and carpel, a potato flower has stamens and carpels, and a lily flower has stamens and carpels. Find the number of flowers, of stamens and of carpels in the whole garden.
Fabaceae: zygomorphic flower, papilionaceous corolla (standard, two wings, a keel of two joined petals), ten stamens with nine joined and one free, one carpel, a legume, root nodules. Solanaceae: radial flower, united sepals and petals, five epipetalous stamens, two joined carpels, a berry or a capsule. Liliaceae: a monocot, six tepals in two whorls, six epiphyllous stamens, three joined carpels, a capsule.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Flowers. Pea: . Potato: . Lily: . In all: .
Step 2. Stamens. .
Step 3. Carpels. .
Answer: flowers, stamens and carpels.
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