MediumChemistryHigh School (11–12)Coordination Compounds › Werner's Theory, Ligands and NomenclatureNumerical

Find the oxidation state of the metal in each complex…

Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

Find the oxidation state of the metal in each complex. Take water, ammonia and carbon monoxide as neutral and chloride and cyanide as $-1$ .

$[\text{Mn}(\text{H}_{2}\text{O})_{6}]^{2+}$
$[\text{CrCl}_{2}(\text{H}_{2}\text{O})_{4}]^{+}$
$[\text{Ni}(\text{CN})_{4}]^{2-}$
$[\text{PtCl}_{4}(\text{NH}_{3})_{2}]$
$[\text{Cr}(\text{CO})_{6}]$

Need a reminder? The key ideaShow

The coordination number is the number of donor atoms bonded to the metal, not the number of ligands. The charge on a complex is $x + (\text{sum of the ligand charges})$ , where $x$ is the oxidation state of the metal. A ligand with two or more donor atoms is chelating, and EDTA has six.

The worked solution

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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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