Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
An iron key is to be plated with nickel. It hangs in a solution of nickel sulphate, and a bar of nickel is the other electrode. (a) Should the key be the anode or the cathode? (b) Write the half-reaction at each electrode. (c) Which terminal of the battery is the key joined to? (d) What happens to the concentration of the solution as the plating goes on?
In an electrolytic cell the anode is joined to the positive terminal of the battery and oxidation happens there. The cathode is negative and reduction happens there. At the cathode the species with the higher reduction potential is reduced, and water is a rival at . At the anode the species with the lower potential is oxidised, and water is a rival at about . An active electrode can dissolve.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. The solution holds ions and sulphate ions.
Step 1. The key. Nickel ions must be reduced to nickel on the key, and reduction happens at the cathode. So the key is the cathode.
Step 2. The half-reactions. At the key: . At the nickel bar, which is the anode: .
Step 3. The terminal. The cathode is joined to the negative terminal of the battery. So the key goes to the negative terminal and the nickel bar to the positive one.
Step 4. The solution. One nickel ion is made at the anode for each one used at the cathode. The concentration does not change.
Answer: the key is the cathode, joined to the negative terminal. The nickel bar dissolves and the key gains a nickel coat, while the solution stays the same.
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