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Acidified dichromate oxidises tin(II) ions to tin(IV) ions…

Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

Acidified dichromate oxidises tin(II) ions to tin(IV) ions. Balance $\text{Cr}_2\text{O}_7^{2-} + \text{Sn}^{2+} \rightarrow \text{Cr}^{3+} + \text{Sn}^{4+}$ by the half-reaction method.

Need a reminder? The key ideaShow

In acid: balance the atoms, then oxygen with $\text{H}_2\text{O}$ , hydrogen with $\text{H}^+$ , and charge with electrons. In base, add $\text{OH}^-$ to both sides to remove the $\text{H}^+$ . Make the electrons equal, add the halves, and cancel.

The worked solution

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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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